easy question just a porblem with the unit........?
2008-01-24 3:25 pm
determine, the area in square feet,of the smallest square that contain a circle with a radius of 8 feet.
回答 (5)
2008-01-24 3:30 pm
✔ 最佳答案
In order to contain this circle the square has to have a side at least as long as the circle's radius. Since we want the smallest square, its side will be twice the radius, which is 16.The area of a square is side squared, and in this case:
16 * 16 = 256 sq. ft.
Hope I helped. :)
nadavs
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2008-01-24 3:41 pm
8 feet x 2 x 8 feet x 2
= 16 feet x 16 feet
= 256 square feet
= 16 feet x 16 feet
= 256 square feet
2008-01-24 3:34 pm
Side of the square = diameter of the circle = 16
area = 16 x 16 = 256 sq feet.
area = 16 x 16 = 256 sq feet.
2008-01-24 3:33 pm
science the radius is 8 feet ,hence the side of square is 16 feet, there fore area is 16*16=256 feet^2
2008-01-24 3:31 pm
radius of circle = 8 feet
therefore, diameter of circle = 16 feet
hence the side of the square = 16 feet
and area of square = side X side = 16 feet X 16 feet
= 256 square feet
therefore, diameter of circle = 16 feet
hence the side of the square = 16 feet
and area of square = side X side = 16 feet X 16 feet
= 256 square feet
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