(x-2)＾2-(x-2)-72=??
急，快!!!!!
中二數題=====(x-2)＾2-(x-2)-72
2008-01-24 11:55 pm
回答 (5)
2008-01-25 1:57 am
✔ 最佳答案
(x-2)^2-(x-2)-72=(x-2)*(x-2)-x+2-72
=x^2-4x+4-x-70
=x^2-5x-66
=(x-11)(x+6)
2008-01-25 2:34 am
ANS:
(x-2)^2-(x-2)-72
=x^2-4x+4-x+2-72
=x^2-5x-66
=(x-11)(x+6)
(x-2)^2-(x-2)-72
=x^2-4x+4-x+2-72
=x^2-5x-66
=(x-11)(x+6)
2008-01-25 1:18 am
(x-2)²-(x-2)-72
=(x-2)(x-2-1)-72
=(x-2)(x-3)-72
=x²-5x+6-72
=x²-5x-66
=(x-11)(x+6)
=(x-2)(x-2-1)-72
=(x-2)(x-3)-72
=x²-5x+6-72
=x²-5x-66
=(x-11)(x+6)
2008-01-25 12:03 am
(x-2)＾2-(x-2)-72
=[(x-2)-9][(x-2)+8]
=(x-11)(x+6)
=[(x-2)-9][(x-2)+8]
=(x-11)(x+6)
收錄日期: 2021-04-23 21:50:55
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080124000051KK01541