three points:
(-3, 3√3 - 4), (0, -4), and (3, 3√3 - 4)
form the verticees of an equilateral triangle. find the equation of the parabola that passes through these three points?
i cant even figure out where to begin =[
math related question verticees?
2008-01-23 8:59 pm
回答 (1)
2008-01-23 9:20 pm
✔ 最佳答案
Formula for parabola: y = a * x^2 + b, where a, b are some constants.You have (0, -4), which is a y-intercept. Therefore, b = -4.
Now, y = a * x^2 - 4. You have to find a. Plug in (x,y) = (-3, 3*sqrt(3) - 4) in the equation.
You will get a = sqrt(3) / 3.
Therefore your parabola is y = ( sqrt(3) / 3 )* x^2 - 4.
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