{ 3x/2 + y = 15 ...... (1)
{ 9x - 2y = 18 ........(2)
From (1), y = 15 - 3x/2 ...... (3)
Sub. (3) into (2), we have
9x -2(15 - 3x/2) = 18
9x - 30 + 3x = 18
9x + 3x = 18 + 30
12x = 48
x = 48/12
x = 4 ...... (4)
Sub. (4) into (3)
y = 15 - 3(4)/2
= 15 - 6
= 9
Therefore, x = 4 and y = 9.
For this problem, method of elimination will be more appropriate.