方程-0-
112+4r =200
一d數學問題(一條)
2008-01-24 2:43 am
回答 (11)
2008-01-24 5:36 am
✔ 最佳答案
112+4r =200112+4r-112=200-112－－首先將兩邊同時減去112，因為要把4r剩下來。
4r=88－－200減112等於88。
4r/4=88/4－－之後兩邊同時除去4，令到左邊只剩r。
r=22//－－這樣就會得出答案22。
2008-01-24 8:32 am
112+4r =200
4r=200-112
4r=88
r=22
4r=200-112
4r=88
r=22
2008-01-24 4:55 am
112+4r=200
4r=200-112
4r=88
r=22
4r=200-112
4r=88
r=22
2008-01-24 4:01 am
112+4r =200
4r=200-112
4r=88
r=22
4r=200-112
4r=88
r=22
2008-01-24 3:00 am
112+4r =200
112+4r -112 =200-112
4r /4 =88/4
r =22
112+4r -112 =200-112
4r /4 =88/4
r =22
2008-01-24 2:56 am
112+4r =200
4r =200-112
r = 88
2008-01-23 18:59:02 補充：
112 4r =200 4r =200-112 r = 88÷4 r =22sorry.. 答錯左'''
4r =200-112
r = 88
2008-01-23 18:59:02 補充：
112 4r =200 4r =200-112 r = 88÷4 r =22sorry.. 答錯左'''
參考: me- _____________-
2008-01-24 2:55 am
樓上果位有少少錯
4r÷8=88÷8
呢步之後應該係
1/2r=11
r=22
4r÷8=88÷8
呢步之後應該係
1/2r=11
r=22
2008-01-24 2:47 am
方程
112+4r =200
4r=200-112
4r=88
r=22
112+4r =200
4r=200-112
4r=88
r=22
收錄日期: 2021-04-13 15:01:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080123000051KK02495