數學問題(Loss&profit)

Q: Mr. Lam buys 50 dozen apples for $720 and he finds that 10%
of them are rotten. If he wants to make a profit of 50% with the
remaining apples. What should be the selling price of each apple?
Sol:
50 × ( 1 － 10% )
＝ 50 × 0.9
＝ 45 ....... remaining dozen apples
45 × 12 ＝ 540 ....... remaining apple
720 × ( 1 ＋ 50% ) ＝ 1080 ....... total selling price
1080 / 540
＝ 2 ....... selling price for each apple
Ans: $2
Send me a letter if any steps you don’t understand.

Very good ~ !

Total no. of apples bought : 50 x 12 = 600
No of good apples remained : 600 x 90% = 540
With 50% profit, total amount should be : 720 x 150% = $1,080
Selling price of each apple : 1,080 / 540 = $2

In order to get 50% profit, each apple should be sold at $2.00

The number of remaining apples
=50x12x90%
=540

The selling price of each apple The selling price of each apple
=$[720(1+50%)]/540 =$[(720+720x50%)/540]
=$(720x150%)/540 OR =$[(720+360)/540]
=$(720x1.5)/540 =$1080/540
=$1080/540 =$2
=$2


The selling price of each apple should be $2.


順道教你:
Selling price = cost price (1 + profit per cent) OR
Selling price = cost price + cost price x profit per cent



Hope my answer can help you!!~

Total no. of apples bought : 50 x 12 = 600
No of good apples remained : 600 x 90% = 540
With 50% profit, total amount should be : 720 x 150% = $1,080
Selling price of each apple : 1,080 / 540 = $2

In order to get 50% profit, each apple should be sold at $2.00

no of the apple which can sell
50X0.9X12 (因為買左50打apple 要計有幾多個就要成番12)
= 540個
let the selling price of each apple be y
(540y-720)/720 x 100% = 50% (只要我張唔係 rotten 既apple成番y - 個cost之後再除番個cost then 成埋100%等於50% )
(540y-720) /720 = 0.5
540y-720 = 360
540y = 1080
y = 2

The selling price of each apple is $2

Total no. of apples bought : 50 x 12 = 600
No of good apples remained : 600 x 90% = 540
With 50% profit, total amount should be : 720 x 150% = $1,080
Selling price of each apple : 1,080 / 540 = $2

In order to get 50% profit, each apple should be sold at $2.00