一條數學題(i think it is very difficult )

It should be 6^5.
You may consider single dice first, it have six face. That means that it has six events, name 1,2,3,4,5 and 6.
Then you consider two dice case, for the first dice, it have six possible outcome, for the second dice it also have six possible outcome. Therefore the total events would be 6 X 6. (1+1,1+2,1+3.....2+5,2+6).

Therefore for 5 dice cases the possible outcome is 6^5 =
7776.

2008-01-22 17:50:47 補充：
As the events so happened was independent for the 5 dices, therefore, answer is 6^5.

it shoud be 5^6 = 15625

1) the 1st die "1" + the 2nd die "1" + ... + the 5th die "1"
2) the 1st die "1" + the 2nd die "2" + ... + the 5th die "1"
...
15625) the 1st die "6" + the 2nd die "6" + ... + the 5th die "6"

2008-01-26 23:07:28 補充：
it should be 6^5 = 7776 (i.e. 6 x 6 x 6 x 6 x 6)as I explained before (D = Dice)roll 1: D1=1, D2=1, D3=1, D4=1, D5=1 >> 1+1+1+1+1roll 2: D1=1, D2=1, D3=1, D4=1, D5=2 >> 1+1+1+1+2...roll 7776: D1=6, D2=6, D3=6, D4=6, D5=6 >> 6+6+6+6+6