數學題 二次一次方程....

2008-01-21 4:52 am

回答 (1)

2008-01-21 5:42 am
✔ 最佳答案
3(13-x) = 5y-11

39 - 3x = 5y - 11

- 3x = 5y - 50

x = (50-5y)/3

2(x+y) = 5y-11

2x + 2y = 5y-11

2x = 3y - 11

x = (3y-11)/2

(50-5y)/3 = (3y-11)/2

100 -10y = 9y - 33

133 = 19y

y = 7

x = (3*7-11)/2 = 10/2 = 5

so, x=5, y=7
參考: 自己


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