If log a^2 = (log a)^2, then a = ?
回答 (4)
2008-01-20 4:12 am
log a^2 = (log a)^2
2log a-(log a)^2=0
(log a)^2-2log a+1=1
(log a-1)^2=sqrt.(1)
log a=1+1 or log a=-1+1
log a=2 or log a=0
a=100 or a=1
2log a-(log a)^2=0
(log a)^2-2log a+1=1
(log a-1)^2=sqrt.(1)
log a=1+1 or log a=-1+1
log a=2 or log a=0
a=100 or a=1
2008-01-19 10:39 pm
log a ^2 = ( log a )^2
( log a )^2 - log a ^ 2 = 0
( log a )^2 - 2 log a = 0
( log a ) (log a - 2)=0
log a =0 or log a - 2=0
a = 1 or log a = 2
a=1 or a = 100
( log a )^2 - log a ^ 2 = 0
( log a )^2 - 2 log a = 0
( log a ) (log a - 2)=0
log a =0 or log a - 2=0
a = 1 or log a = 2
a=1 or a = 100
2008-01-19 9:23 pm
log a^2 =(log a)^2
2 log a=(log a)^2
(log a)^2 - 2 log a = 0
(log a)(log a - 2) = 0
log a = 0 or 2.
a = 1 or 100.
2 log a=(log a)^2
(log a)^2 - 2 log a = 0
(log a)(log a - 2) = 0
log a = 0 or 2.
a = 1 or 100.
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