How to do ? In(x+8)-Inx=1?
回答 (2)
2008-01-18 11:26 pm
✔ 最佳答案
In(x+8)-Inx = 1ln[(x+8)/x] = 1
(x+8)/x = e
1 + 8/x = e
8/x = e-1
x = 8/(e-1)
2008-01-18 11:28 pm
In(x+8)-Inx = 1
Inx + in8 - Inx = 1
In8 = 1
In = 1/8
Inx + in8 - Inx = 1
In8 = 1
In = 1/8
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