How to do ? In(x+8)-Inx=1?

In(x+8)-Inx = 1

ln[(x+8)/x] = 1

(x+8)/x = e

1 + 8/x = e

8/x = e-1

x = 8/(e-1)

In(x+8)-Inx = 1
Inx + in8 - Inx = 1
In8 = 1
In = 1/8