上面右邊(n+1)(n+2)是怎出來的?
更新1:
OKOK 我知道了
數列的計算 急１５點
2008-01-18 8:27 am
{ (-3)(-4)(-5)....[-(n+2)] }/n!={ (-1)*^n*2*3*4*5...(n+1)(n+2)} / 2n!
上面右邊(n+1)(n+2)是怎出來的?
上面右邊(n+1)(n+2)是怎出來的?
回答 (2)
2008-01-19 8:19 am
✔ 最佳答案
It should be = ={ (-1)^n *2*3*4*5...(n+1)(n+2)} / 2n! on the right hand side.You can 2 on both top and bottom. It will make:
(-1)^(n){3*4*...*(n+1)(n+2)}/n!
2008-01-18 11:01 am
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080118000010KK00264