甲乙二數的和是72,甲比乙大14,求甲、乙各多少???(方程式)
(請列式and點樣計)
(甲、乙各多少?)
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甲乙二數的和是72,甲比乙大14,求甲、乙各多少???
2008-01-18 4:33 am
回答 (7)
2008-01-18 4:54 am
有關計算formula如下:
先假設 甲=x and 乙=y,
然後代入有關程式, 變成 x+y = 72 and x-y = 14,
跟著將兩條等式相加(你也可選擇相減),
變成 x+y-(x-y) = 72-14,
2y = 58,
y = 29.
然後再將 y 代入以上第1條等式(其實可選擇任何1條等式),
再求出x.
變成 x+y = 72,
x+29 = 72,
x = 43.
答案: 甲是43, 而乙是29.
先假設 甲=x and 乙=y,
然後代入有關程式, 變成 x+y = 72 and x-y = 14,
跟著將兩條等式相加(你也可選擇相減),
變成 x+y-(x-y) = 72-14,
2y = 58,
y = 29.
然後再將 y 代入以上第1條等式(其實可選擇任何1條等式),
再求出x.
變成 x+y = 72,
x+29 = 72,
x = 43.
答案: 甲是43, 而乙是29.
2008-01-18 4:50 am
Let x be B
(x+14) +x = 72
2x+14=72
2x=72-14
x= 58/2
x=29
because A is greater than B
so A = 29+14
A = 43
(x+14) +x = 72
2x+14=72
2x=72-14
x= 58/2
x=29
because A is greater than B
so A = 29+14
A = 43
參考: me
2008-01-18 4:47 am
甲 + 乙 = 72
甲 = 乙 + 14
=> (乙 + 14 ) + 乙 = 72
2乙 + 14 = 72
2乙 = 58
乙 = 29#
甲 = 乙 + 14
甲 = 43#
甲 = 乙 + 14
=> (乙 + 14 ) + 乙 = 72
2乙 + 14 = 72
2乙 = 58
乙 = 29#
甲 = 乙 + 14
甲 = 43#
參考: me
2008-01-18 4:47 am
.對不起，我不懂。。
2008-01-18 4:44 am
a+b=72
a-b=14
2b=58
b=19
a=33
a-b=14
2b=58
b=19
a=33
收錄日期: 2021-04-13 15:01:21
原文連結 [永久失效]:
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