Math!
回答 (6)
2008-01-18 1:54 am
✔ 最佳答案
This is a A.S.a= 1
d= 2
1 + 2(n-1) = 2003
2n-1 = 2003
2n = 2004
n = 1002
1002(2003+1)/2
=2004*501
=1004004
2008-01-22 2:49 am
2003+2001+1999+1997+...+1007+1005-1003-1001-999-997-...-3-1=498996
2008-01-18 2:26 am
2003+2001+1999+1997+...+1007+1005-1003-1001-999-997-...-3-1
=(2003-1003) + (2001-1001) + (1999 - 999) + ... + (1005 -5) -3 -1
=1000+1000+1000+...+1000-3-1
=499(1000)-3-1
=499000-3-1
=498996
=(2003-1003) + (2001-1001) + (1999 - 999) + ... + (1005 -5) -3 -1
=1000+1000+1000+...+1000-3-1
=499(1000)-3-1
=499000-3-1
=498996
2008-01-18 2:06 am
[500(1005+2003)]/2-[503(1+1003)]/2
=499494
=499494
2008-01-18 2:05 am
（2003+1005)/2x ((2003-1005)/2+1)-(1003+1)/2x((1003-1)/2+1)
=3008/2 x (998/2+1) - 1004/2 x (1002/2+1)
=1504 x (499+1) - 502 x (501+1)
=1504 x 500- 502 x 502
=752000 - 252004
=499996
=3008/2 x (998/2+1) - 1004/2 x (1002/2+1)
=1504 x (499+1) - 502 x (501+1)
=1504 x 500- 502 x 502
=752000 - 252004
=499996
參考: me
2008-01-18 1:56 am
=(2003-1003)x(2003-1003)/2
=1000x500
=500000
2008-01-17 17:59:57 補充：
更正=(2003-1003)x(2003+1)/2=1000x1002=1002000
=1000x500
=500000
2008-01-17 17:59:57 補充：
更正=(2003-1003)x(2003+1)/2=1000x1002=1002000
收錄日期: 2021-04-13 14:58:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080117000051KK02337