y=-0.12(x+2.04)^2+7.62 << 表達式一
y= -0.12(x^2)+0.4896x+7.120608 <<< 表達式二
找出 表達式一 和 表達式二 的係數關係...?
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2008-01-17 2:38 am
回答 (2)
2008-01-17 2:43 am
✔ 最佳答案
代番入去就得put 表達式二 into 表達式一
-0.12(x^2)+0.4896x+7.120608 = -0.12(x+2.04)^2+7.62
參考: me
2008-01-17 3:17 am
0.12x^2+0.4896x....(i)
y= -0.12(x^2)+0.4896x+7.120608.....(ii)
y=-0.12(x+2.04)^2+7.62
= -0.12(x^2)+0.4896x+7.120608
-0.12(x^2)+0.4896x+7.120608 =-0.12(x+2.04)^2+7.62
0.12(x^2 +4.1616)+0.499392=0.12x^2+0.4896x
0.12 x^2+0.499392+0.499392=0.12x^2+0.4896x
0.998784=0.4896x
x=2.04..........(iii)
代x=2.04 入(i),
y=0.12x^2+0.4896x
y=0.12(2.04)^2+0.4896(2.04)
y=0.12(4.1616)+0.998784
y=0.499392+0.998784
y=1.498176
so x=2.04,y=1.498176
2008-01-16 19:24:16 補充：
ok????
y= -0.12(x^2)+0.4896x+7.120608.....(ii)
y=-0.12(x+2.04)^2+7.62
= -0.12(x^2)+0.4896x+7.120608
-0.12(x^2)+0.4896x+7.120608 =-0.12(x+2.04)^2+7.62
0.12(x^2 +4.1616)+0.499392=0.12x^2+0.4896x
0.12 x^2+0.499392+0.499392=0.12x^2+0.4896x
0.998784=0.4896x
x=2.04..........(iii)
代x=2.04 入(i),
y=0.12x^2+0.4896x
y=0.12(2.04)^2+0.4896(2.04)
y=0.12(4.1616)+0.998784
y=0.499392+0.998784
y=1.498176
so x=2.04,y=1.498176
2008-01-16 19:24:16 補充：
ok????
參考: 在下
收錄日期: 2021-04-13 14:58:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080116000051KK02755