✔ 最佳答案
a)
Molar mass of C = 12.01 g mol-1
Molar mass of H = 1.008 g mol-1
Molar mass of O = 16.00 g mol-1
Consider 1.53 g of the compound.
Mass of C = Mass of C in CO2 = 2.24 x (12.01/44.01) = 0.611 g
Mass of H = Mass of H in H2O = 0.918 x (2.016/18.016) = 0.103 g
Mass of O = 1.53 - (0.611 + 0.103) = 0.816 g
Mole ratio C : H : O
= (0.611/12.01) : (0.103/1.008) : (0.816/16)
= 1 : 2 : 1
Hence, empirical formula = CH2O
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b)
Let (CH2O)n be the molecular formula of the compound.
(12.01 + 1.008 x 2 + 16)n = 60.03
n = 2
Hence, molecular formula = C2H4O2