f.2 maths
回答 (4)
✔ 最佳答案
(x-1)/a - b =x
(x-1) -ab =ax
(x-1) -ax = ab
x-ax-1 =ab
x-ax = ab+1
x (1 -a) =ab+1
x= (ab + 1) / (1 -a)
x - 1/a -b =x
x - 1/a =x - b
x - 1/a - x= - b
x - 1 - ax = - ab
x - ax = -ab + 1
x(1 - a) = -ab + 1
x = (-ab + 1)/(1 - a)
參考: me
x-1
---- -b =x
a
x-1
---- =x+b
a
x-1=(x+b)a
x-1=ax+ab
x-1-ax=ab
x-ax=ab+1
x(1-a)=ab+1
ab+1
x =-------
1-a
參考: 自己
x - 1 - ab
------------- = x
a
x - 1 - ab = ax
x - ax = 1 + ab
x (1 - a) = 1 + ab
x = (1 + ab)
-----------
(1 - a)
收錄日期: 2021-04-29 14:19:23
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