2. Jack and Jane share a sum of $6000. Then Jack gives some of hios money to Jane. If Jane's share is increase by 15% and becomes $1380, find the percantage decrease in Jakc's share.
3. A man sells twomachines at $19800 each. He makes a profit of 10% on one machine and suffers a loss of 10% on one other. On the whole, find
(a) his profit or loss
(b) fis profit % or loss %.
數學題(20分)
2008-01-15 4:26 am
回答 (2)
2008-01-15 4:44 am
✔ 最佳答案
2.Let y be Jane 's share.
1.15y=1380
y=1200
The percantage decrease in Jack's share:
180/4800*100%
=3.75%
Ans:The percantage decrease in Jack's share is 3.75%.
3a.
$19800*2-[$19800*(1+10%)+$19800*(1-10%)]
=$0
Ans: He does not have profit or loss.
3b.Beacuse he does not have any profit or loss so he does not have profit % or loss %.
參考: me
2008-01-17 11:52 pm
2.
Jane's share = $1,380/(1 + 15%) = $1,200
Jack's share = $6,000 - $1,200 = $ 4,800
The money Jack gives Jane = $1,380 - $1,200 = $180
% decrease in Jack's share = 180/4800 = 3.75%
3.
Cost of the profit machine = $19,800/(1 + 10%) = $18,000
Cost of the loss machine = $19,800/(1 - 10%) = $22,000
Total cost of the two machines = $18,000 + $22,000 = $40,000
Total selling = $19,800 x 2 = $39,600
(a) Therefore his loss = $40,000 - $39,600 = $400
(b) His loss % = 400/40000 = 1%
Jane's share = $1,380/(1 + 15%) = $1,200
Jack's share = $6,000 - $1,200 = $ 4,800
The money Jack gives Jane = $1,380 - $1,200 = $180
% decrease in Jack's share = 180/4800 = 3.75%
3.
Cost of the profit machine = $19,800/(1 + 10%) = $18,000
Cost of the loss machine = $19,800/(1 - 10%) = $22,000
Total cost of the two machines = $18,000 + $22,000 = $40,000
Total selling = $19,800 x 2 = $39,600
(a) Therefore his loss = $40,000 - $39,600 = $400
(b) His loss % = 400/40000 = 1%
收錄日期: 2021-04-13 19:50:06
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