Help with my A-math!!

1. Find the equation of a straight like which is concurrent with the lines x+y-2=0 and y-2x-2=0 and the sum of the intercepts is equal to 6
The point of intersection of the two lines is (0,2)
As the sum of the intercepts is equal to 6, the line passes throught x-intercept is 4 ie(4,0)
Hence, the equation of the straight line is
( y - 2 ) / ( x - 0 ) = ( y - 0 ) / ( x - 4 )
x + 2y - 4 = 0
2. A straight line L passes through the point (1,3). if the area of the triangle enclosed by the line L and the positive axes is 25/4 sq.units, find the quations of L.
Let (m,0) and (0,n) are the two point of x-intercept and y-intercept.
mn / 2 = 25/4
m = 25/2n

As the line passes through the point (1,3), then
( 25/2n - 3 ) / ( 0 - 1 ) = ( 0 - 3 ) / ( n - 1 )
6n^2 - 25n + 25 = 0
n = 5/2 or 5/3
Hence, the straight line is
( y - 3 ) / ( x - 1 ) = ( y - 0 ) / ( x - 5/2) or ( y - 3 ) / ( x - 1 ) = ( y - 0 ) / ( x - 5/3)
2x + y - 5 = 0 or 9x + 2y - 15 = 0