一題maths題
2008-01-14 3:09 am
有一樽果汁....啊a飲左 1/4...啊b飲左剩低0既 2/5...啊c飲左之後剩低0既 4/9....樽裏面仲有200mL0既果汁....呢樽果汁本身有幾mL??
回答 (6)
2008-01-14 3:37 am
✔ 最佳答案
y*(1-1/4)*(1-2/5)*(1-4/9)=200y*3/4*3/5*5/9=200
y=800
或
200/(1-1/4)/(1-2/5)/(1-4/9)
=200/ 3/4 / 3/5 / 5/9
=800ml
參考: me
2008-01-15 1:55 am
800 ml
2008-01-14 3:38 am
設呢樽果汁本身有 A mL,
A ×1/4x2/5x4/9=200
Ax8/180=200
Ax2/45=200
Ax2/45÷2/45=200÷2/45
A=200x45/2
A=4500
或
200÷1/4÷2/5÷4/9
=200x4/1x5/2x9/4
=800x5/2x9/4
=2000×9/4
=4500
A ×1/4x2/5x4/9=200
Ax8/180=200
Ax2/45=200
Ax2/45÷2/45=200÷2/45
A=200x45/2
A=4500
或
200÷1/4÷2/5÷4/9
=200x4/1x5/2x9/4
=800x5/2x9/4
=2000×9/4
=4500
2008-01-14 3:27 am
設原有果汁x mL
x(1-1/4)(1-2/5)(1-4/9)=200
1/4(x)=200
x=800
所以原有果汁800ml
x(1-1/4)(1-2/5)(1-4/9)=200
1/4(x)=200
x=800
所以原有果汁800ml
2008-01-14 3:25 am
設：原本有 k mL果汁
(1-4/9)(1-2/5)(1-1/4)k=200
(5/9)(3/5)(3/4)k=200
k=800
原本有800mL果汁~
(1-4/9)(1-2/5)(1-1/4)k=200
(5/9)(3/5)(3/4)k=200
k=800
原本有800mL果汁~
2008-01-14 3:23 am
let c be the volume of the juice
[(1 - 1/4) x (1- 2/5) x (1 - 4/9)]c = 200
(3/4 x 3/5 x 5/9)c = 200
(1/4)c = 200
c = 800 mL
[(1 - 1/4) x (1- 2/5) x (1 - 4/9)]c = 200
(3/4 x 3/5 x 5/9)c = 200
(1/4)c = 200
c = 800 mL
參考: 自己計
收錄日期: 2021-04-13 17:18:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080113000051KK03518