問
sin (90+x)=?
cos(90+x)=?
tan (90+x)=?
sin(270+x)=?
cos(270+x)=?
tan(270+x)=?
sin(270-x)=?
cos(270-x)=?
tan(270-x) =?
明我up 乜就答啦
中4 sin cos tan 公式
2008-01-13 6:25 pm
回答 (2)
2008-01-13 6:53 pm
✔ 最佳答案
sin (90+x)= cos xcos(90+x)= - sin x
tan (90+x)= - 1/ tan x
sin(270+x)= -cos x
cos(270+x)= sin x
tan(270+x)= - 1/tan x
sin(270-x)= -cos x
cos(270-x)= -sin x
tan(270-x) = 1/tan x
2008-01-13 7:21 pm
sin (90+x)
=sin(180-(90-x))
=sin(90-x)
=cosx
cos(90+x)
=cos(180-(90-x))
=-cos(90-x)
=-sinx
tan (90+x)
=tan(180-(90-x))
=-tan(90-x)
=-1/tanx
sin(270+x)
=sin(360-(90-x))
=-sin(90-x)
=-cosx
cos(270+x)
=cos(360-(90-x))
=cos(90-x)
=sinx
tan(270+x)
=tan(360-(90-x))
=-tan(90-x)
=-1/tanx
sin(270-x)
=sin(360-(90-x))
=-sin(90+x)
=-cosx
cos(270-x)
=cos(360-(90+x))
=cos(90+x)
=-sinx
tan(270-x)
=tan(360-(90+x))
=-tan(90+x)
=1/tanx
希望能夠幫到你~
=sin(180-(90-x))
=sin(90-x)
=cosx
cos(90+x)
=cos(180-(90-x))
=-cos(90-x)
=-sinx
tan (90+x)
=tan(180-(90-x))
=-tan(90-x)
=-1/tanx
sin(270+x)
=sin(360-(90-x))
=-sin(90-x)
=-cosx
cos(270+x)
=cos(360-(90-x))
=cos(90-x)
=sinx
tan(270+x)
=tan(360-(90-x))
=-tan(90-x)
=-1/tanx
sin(270-x)
=sin(360-(90-x))
=-sin(90+x)
=-cosx
cos(270-x)
=cos(360-(90+x))
=cos(90+x)
=-sinx
tan(270-x)
=tan(360-(90+x))
=-tan(90+x)
=1/tanx
希望能夠幫到你~
參考: 自己~
收錄日期: 2021-04-16 12:16:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080113000051KK00887