math equation

👨🏻‍🏫 學術台數學

youlikeido

2008-01-12 8:00 am

-3( k^3 - k) + 2k = 2k

how to solve,please complete answer...^^

回答 (3)

toyszchun

2008-01-12 8:07 am

✔ 最佳答案

-3( k^3 - k) + 2k = 2k
-3( k^3 - k) = 0
k^3 - k = 0
k(k^2 - 1) = 0
k(k - 1)(k + 1) = 0
k = 0 or 1 or -1

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dickyman

2008-01-14 2:13 am

-3( k^3 - k) = 0
-3k^3+3k=0
k(-3k^2+3)=0
k=0 or k=1

參考: F.1

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[匿名]

2008-01-12 8:18 am

-3(k^3-k)+2k=2k
-3k^3+3k+2k=2k
-3k^3+5k=2k
-3k^3=2k-5k
-3k^3=-3k
k^3=-3k/-3
k^3=k
k=0
Ans:The solution is k=0.

參考: me

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