Z1=1-j3 Z2=-2-j5,determine in a+jb form:
Z1Z2/Z1+Z2
engineering Maths
2008-01-12 7:28 am
回答 (1)
2008-01-12 6:20 pm
✔ 最佳答案
Z1=1-3j Z2=-2-5jZ1+Z2 =-1-8j
Z1Z2=(1-3j)(-2-5j)=-2+6j-5j-15=-17+j
Z1Z2/Z1+Z2
=(-17+j)/(-1-8j)
=(-17+j)(-1+8j)/(-1-8j)(-1+8j)
=(9-137j)/65
=(9/65)-(137/65)j
收錄日期: 2021-04-25 16:55:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080111000051KK04472