evaluate:
a, 6(x^1/2)dx
b, 3/(x^2)dx
c, 5/(x^1/2)dx
d,x^1/2(1-x)dx
Integration一問
2008-01-11 7:25 am
回答 (2)
2008-01-13 1:39 am
✔ 最佳答案
a) 6(x^1/2)dx =6(x^3/2)/(3/2)+C =4(x^3/2)+C where C is a constantb)3/(x^2)dx=-3/x+C where C is a constant
c)5/(x^1/2)dx=5(x^1/2)/(1/2)+C=10x^(1/2)+C where C is a constant
d)x^1/2(1-x)dx =2/3 x^(3/2)+ 2/5 x^(5/2)+C where C is a constant
參考: actually they're just some simple integration questions, so do more practice !
2008-01-11 7:32 am
a) 4(x^3/2)+C
b)-3/x+C
c)10x^(1/2)+C
d) 2/3 x^(3/2)+ 2/5 x^(5/2)+C
b)-3/x+C
c)10x^(1/2)+C
d) 2/3 x^(3/2)+ 2/5 x^(5/2)+C
參考: ME
收錄日期: 2021-04-14 19:08:41
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