指數定律 f.3

2008-01-11 2:46 am
(2d^3e^2)^5=


(2xy^2)^4=

(3^6)5=

(125^5)^-1=

7^-2=

(b^3)-0=

(xy^3)^-2=

(a^3b^-7)^2=

(a^0)^-2=


答案唔要以指數表示,,((數字果d答案)) 例如:10^3x10^5=10^3+5=10^8=100000000

回答 (1)

2008-01-11 3:02 am
✔ 最佳答案
(2d^3e^2)^5=32d^15e^10


(2xy^2)^4=16x^4y^8

(3^6)5=3^30=2.06X10^14

(125^5)^-1=1/125^5=1/(3.05X10^10)

7^-2=1/(7^2)=1/49

(b^3)-0=b^3 [若是(b^3)^0=1]

(xy^3)^-2=1/(x^2y^6)

(a^3b^-7)^2=a^6/b^14

(a^0)^-2=1^-2=1


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