-2(6 - 2x) = 4(-3 + x)?

- 12 + 4x = - 12 + 4x
Dodgy question!!!!!!!

yes.

what i mean is '-2(6-2x' is same as '4(-3+x)'
so -2(6-2x) = 4(-3+x)

-2(6 - 2x) = 4(-3 + x)
-12 + 4x = -12 + 4x
-4x + 4x = -12 + 12
0 = 0

No solution.

it has infinitive solution sets

they are equal..
it will become
1=1
why?
because when you distribute it..it will become like this:
-12+4x = -12+4x
you will cancel out the -12 and it will left:
4x = 4x
you may cancel out both of them and will remain an answer of 1.

-12+4x=-12+4x
4x-4x=-12+12
0

-2(6 - 2x) = 4(-3 + x)
=> -12 + 4x = -12 + 4x....
=> so x =0....


proof...

-2(6 - 2x) = 4(-3 + x)
-2(6- 0) = 4( -3+0)
-12= -12...
Hence proved....

-2(6 - 2x) = 4(-3 + x)?
distribute...
-12 + 4x = -12 + 4x
it can be 0=0 or 1=1 or x=x

if what you did is like this..........
-12 + 4x = -12 + 4x
4x - 4x = 12 -12
the answer would be 0=0

but if you divide the equation by -12+4x.................
-12 + 4x = -12 + 4x
(-12 + 4x)/ (-12 + 4x) = (-12 + 4x)/(-12 + 4x)
the answer would be 1=1

if you did this........
-12 + 4x = -12 + 4x
4x=12-12 +4x
4x=4x..........then divide by 4
the answer would be x=x

your answer would base upon on what you will do...
hence.....the equation is equal...

-12+4x=-12+4x
x=x

-2(6-2x)=4(-3+x)
-12+4x=-12+4x
-12+12=-4x+4x
0=x
x=0