解以下聯立方程

I will try

上(1)下(2).
(2)^2,
9k^2+30kh+25h^2=196......(3)
(3)-(1),
30kh+50h^2=140
3kh+5h^2=14
3k+5h=14/h=14
14=14h
h=1
Put h=1 into (2),
3k+5=14
3k=9
k=3

雖然有點牽強，但我只是form one炸！
驗算過，應該冇錯，希望幫到你！

9k^2-25h^2=56--(1)
3k+5h=14--(2)
由(2)可得...
h=(14-3k)5

put into (1)
9k^2-25[(14-3k)5]^2=56
9k^2-196+84k-9k^2=56
84k=252
k=3

put k=3 into (2)
3(3)+5h=14
h=1//

so h=1 and k=3