(A+B)2次方(A+AB)2次方

FIRST WAY:
(A+B)^2(A+AB)^2
=(A^2+B^2)(A^2+A^2B^2)
=A^4+A^4B^2+A^2B^2+A^2B^4
=A^4+A^2B^2(A^2+1+B^2)
=A^2[A^2+B^2(A^2+1+B^2)

OR

SECOND WAY:
(A+B)^2(A+AB)^2
=(A+B)(A+B)(A+AB)(A+AB)
=A^4+B^2+AB^2


HOPE THAT THE FIRST WAY IS CORRECT LA (SEEMS TO BE WRONG [@ X @] )
ALSO HOPE THAT YOU CAN CHOOSE ME AS THE BEST ANSWER LA !
THX!!!!!!!~~~~~~~~

Completely wrong!!!
(A+B)^2(A+AB)^2
=(A+B)^2(A(1+B))^2
=(A+B)^2(A^2)(1+B)^2
=(A(A+B)(1+B))^2

(a+b)²(a+ab)²

=(a+b)(a+b)(a+ab)(a+ab)

=a²+b²+a²+a²b²

=a^6+b^4

This is not factorization.It is expand the polynomial.

(A+B)2次方 :: A 2次方+ 2AB + B2次方

(A+AB)2次方 :: A2次方 + A2次方B + AB2次方

唔知係唔係咁做= =

(A+B)²(A+AB)²

冇得再因式分解la wo!!!

A2次+B2次

A2次+(AB)2次