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(A+B)2次方(A+AB)2次方
回答 (6)
2008-01-20 7:11 am
✔ 最佳答案
FIRST WAY:(A+B)^2(A+AB)^2
=(A^2+B^2)(A^2+A^2B^2)
=A^4+A^4B^2+A^2B^2+A^2B^4
=A^4+A^2B^2(A^2+1+B^2)
=A^2[A^2+B^2(A^2+1+B^2)
OR
SECOND WAY:
(A+B)^2(A+AB)^2
=(A+B)(A+B)(A+AB)(A+AB)
=A^4+B^2+AB^2
HOPE THAT THE FIRST WAY IS CORRECT LA (SEEMS TO BE WRONG [@ X @] )
ALSO HOPE THAT YOU CAN CHOOSE ME AS THE BEST ANSWER LA !
THX!!!!!!!~~~~~~~~
參考: ME(ALREADY USED SOME TIME TO DO THAT GA) VOTE ME! VOTE ME!
2008-01-30 5:36 am
Completely wrong!!!
(A+B)^2(A+AB)^2
=(A+B)^2(A(1+B))^2
=(A+B)^2(A^2)(1+B)^2
=(A(A+B)(1+B))^2
(A+B)^2(A+AB)^2
=(A+B)^2(A(1+B))^2
=(A+B)^2(A^2)(1+B)^2
=(A(A+B)(1+B))^2
2008-01-12 11:21 pm
(a+b)²(a+ab)²
=(a+b)(a+b)(a+ab)(a+ab)
=a²+b²+a²+a²b²
=a^6+b^4
This is not factorization.It is expand the polynomial.
=(a+b)(a+b)(a+ab)(a+ab)
=a²+b²+a²+a²b²
=a^6+b^4
This is not factorization.It is expand the polynomial.
參考: My maths knowledge
2008-01-09 3:02 am
(A+B)2次方 :: A 2次方+ 2AB + B2次方
(A+AB)2次方 :: A2次方 + A2次方B + AB2次方
唔知係唔係咁做= =
(A+AB)2次方 :: A2次方 + A2次方B + AB2次方
唔知係唔係咁做= =
2008-01-09 2:39 am
(A+B)²(A+AB)²
冇得再因式分解la wo!!!
冇得再因式分解la wo!!!
收錄日期: 2021-04-23 20:34:50
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https://hk.answers.yahoo.com/question/index?qid=20080108000051KK02718