proof of a inequality

2008-01-08 6:42 am
my physics teacher state that the root mean square is greater than the A.M. without proof. i wanna try to prove it...

here is my proof, are there any logical errors?

i just think that th proof is not so simple...

http://www.hkedcity.net/sch_files/a/kst/kst-06185/public_html/rms.jpg

回答 (1)

2008-01-08 9:35 am
✔ 最佳答案
It's wrong.
Because (x1+x2+x3+...+xn)^2
= x1^2+x2^2+....xn^2 + 2(x1x2+x1x3+...+x1xn+x2x3+x2x4+x2..+ ..+x(n-1)xn)

Not only x_i . x_i+1

Actually you can use Schwartz inequality
with a_i= x_i, b_i=1
then Sum(i^2) Sum(x_i^2)>= [Sum(x_i)]^2
divide both sides by n and take root, you will get it.
參考: me


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