更新1:
w^4 -1
fACTORIZE (bedore 5"00)
回答 (4)
2008-01-08 12:47 am
✔ 最佳答案
(a-b)-(a+b)(b-a)=(a-b)+(a+b)(a-b)
=(a-b)(1+a+b)
w^4 -1
=(w^2)^2-1
=(w^2-1)(w^2+1)
=(w-1)(w+1)(w^2+1)
2008-01-07 17:13:57 補充：
-(a-b)=(b-a)
2008-01-08 1:14 am
= (a-b)+(a+b)(a-b)
= (a-b)(a+b)
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or ,, this maybe correct--- a^2 + b^2
= (a-b)(a+b)
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or ,, this maybe correct--- a^2 + b^2
2008-01-08 12:54 am
(a-b)-(a+b)(b-a)
=(a-b)-(-a^2+b^2)
=(a+b)-(a^2-b^2)
=(a+b)-(a+b)(a-b)
=(a+b)[(1-(a-b)]
=(a+b)(1-a+b)
w^4-1
=w^2(2)-1
=(w^2+1)-(w^2-1)
=(w^2+1)-(w^2+1)(w^2-1)
=(w^2+1)(1-w^2+1)
=(w^2+1)(2-w^2)
=(a-b)-(-a^2+b^2)
=(a+b)-(a^2-b^2)
=(a+b)-(a+b)(a-b)
=(a+b)[(1-(a-b)]
=(a+b)(1-a+b)
w^4-1
=w^2(2)-1
=(w^2+1)-(w^2-1)
=(w^2+1)-(w^2+1)(w^2-1)
=(w^2+1)(1-w^2+1)
=(w^2+1)(2-w^2)
2008-01-08 12:45 am
(a-b) +(a+b)(a-b)
(a-b)(1+a-b)
(a-b)(1+a-b)
收錄日期: 2021-04-25 17:28:00
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080107000051KK02032