1)3(a-b)(3r-t)+9(b-a)(2t-5s)
=3(a-b)(3r-t)-9(a-b)(2t-5s)
=3(a-b)[(3r-t)-3(2t-5s)]
=3(a-b)(3r-t-6t+15s)
=3(a-b)(3r-7t+15s),,
點解
=3(a-b)(3r-t)-9(a-b)(2t-5s)
=3(a-b)[(3r-t)-3(2t-5s)]???
一個math問題
2008-01-07 10:05 pm
回答 (3)
2008-01-07 10:15 pm
✔ 最佳答案
XY-XZ=X(Y-Z)...去到呢到，你明唔明？
如果無問題，你就當ｘ＝３（ａ－ｂ）
3(a-b)(3r-t)-9(a-b)(2t-5s)
=3(a-b)(3r-t)-3(a-b)*3*(2t-5s)
將3(a-b)抽番出去，咪就係答案ｌｏｒ．．
2008-01-07 10:28 pm
因為
3(a-b)(3r-t)-9(a-b)(2t-5s)
=3(a-b)(3r-t)-3*3(a-b)(2t-5s)
=3(a-b)[3(r-t)-3(2t-5s)]
係將3(a-b)抽出黎=]
3(a-b)(3r-t)-9(a-b)(2t-5s)
=3(a-b)(3r-t)-3*3(a-b)(2t-5s)
=3(a-b)[3(r-t)-3(2t-5s)]
係將3(a-b)抽出黎=]
2008-01-07 10:11 pm
因為- -得+
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收錄日期: 2021-04-14 18:14:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080107000051KK01336