What is 9! in base 13?

9! = 362,880

13^4 = 28561
13^3 = 2197
13^2 = 169
13^1 = 12
13^0 = 1

362,880
= 12*28561 + 9*2197 + 2*169 + 2*13 + 11
= C922B base 13


6 * 9 = 54 = 4*13 + 2 = 42 base 13

Another way. easy.

9! = 362,880

362,880 /13 = 27913 remains 11. Mark 11 as B and put it at the right-most digit.

27913 /13 = ?? remains 2. Put this number as the second right-most digit.

Repeat above until dividend is smaller than divisor.

9! = 9*8*7*6*5*4*3 *2*1 = 362,880


362,880
= C922B (base 13)


6 * 9 = 54 = 4*13 + 2 = 42 (base 13)

9 ! = 362880 That is base 10
362880 in base 13 is C922B

One queston who uses base 13.

Is that 9 factorial? If so, 9*8*7*6*5*4*3*2*1=362880

362880= 12(13^4)+9(13^3)+2(13^2)+2(13^1)+11(13^0)

If you mean 9, then the answer is 9.

Well, in decimal it's 9*8*7*6*5*4*3*2*1 = 362,880 = C922B.

Here is my interactive Python session in which I came up with that result:

>>> 9*8*7*6*5*4*3*2*1
362880
>>> n = 362880
>>> n
362880
>>> n / 13
27913
>>> n%13
11
>>> 27913/13
2147
>>> 27913%13
2
>>> 2147/13
165
>>> 2147%13
2
>>> 165/13
12
>>> 165%13
9
>>> B=13
>>> 12*B**4+9*B**3+2*B**2+2*B+11
362880

9 in ANY base greater than 9 is .... 9.

9 in base 9 would be 10.