What is 9! in base 13?

2008-01-07 3:18 am
更新1:

also, 6 x 9 = 42

回答 (7)

2008-01-07 3:26 am
✔ 最佳答案
9! = 362,880

13^4 = 28561
13^3 = 2197
13^2 = 169
13^1 = 12
13^0 = 1

362,880
= 12*28561 + 9*2197 + 2*169 + 2*13 + 11
= C922B base 13


6 * 9 = 54 = 4*13 + 2 = 42 base 13
2008-01-11 10:56 am
Another way. easy.

9! = 362,880

362,880 /13 = 27913 remains 11. Mark 11 as B and put it at the right-most digit.

27913 /13 = ?? remains 2. Put this number as the second right-most digit.

Repeat above until dividend is smaller than divisor.
2008-01-11 10:32 am
9! = 9*8*7*6*5*4*3 *2*1 = 362,880


362,880
= C922B (base 13)


6 * 9 = 54 = 4*13 + 2 = 42 (base 13)
2008-01-07 12:21 pm
9 ! = 362880 That is base 10
362880 in base 13 is C922B

One queston who uses base 13.
2008-01-07 11:40 am
Is that 9 factorial? If so, 9*8*7*6*5*4*3*2*1=362880

362880= 12(13^4)+9(13^3)+2(13^2)+2(13^1)+11(13^0)

If you mean 9, then the answer is 9.
2008-01-07 11:28 am
Well, in decimal it's 9*8*7*6*5*4*3*2*1 = 362,880 = C922B.

Here is my interactive Python session in which I came up with that result:

>>> 9*8*7*6*5*4*3*2*1
362880
>>> n = 362880
>>> n
362880
>>> n / 13
27913
>>> n%13
11
>>> 27913/13
2147
>>> 27913%13
2
>>> 2147/13
165
>>> 2147%13
2
>>> 165/13
12
>>> 165%13
9
>>> B=13
>>> 12*B**4+9*B**3+2*B**2+2*B+11
362880
2008-01-07 11:22 am
9 in ANY base greater than 9 is .... 9.

9 in base 9 would be 10.
參考: Think about it.


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