有無人可以幫我解f.2 maths題,,急要 (15點)

乜乜的幾多次方的表達式應該係咁的: e.g. , x square 以 x^2 表示
41. (x^6)-64 = [(x^3)^2]-(8^2)=[(x^3)-8][(x^3)+8]
43. 9(a^2)c+ 6a (c^3)–24(c^3)= 3c [3(a^2)+ 2a (c^2)-8(c^2)] ( this can be 1 of answer )
Another answer = 3c {( 3a -12)[a+(2/3)(c^2)]+ 12a }
= … = 3c {(a-4)[ 3a +2(c^2)]+ 12a }
45 . -15(c^2)(d^3)+ 6c (d^3)+9(d^3)= -3(d^3)[5(c^2) -2c -3] = -3(d^3)( 5c +3)(c-1)
47. -34(x^2)y+2(x^4)+32(y^2)= 2[(x^4)-17(x^2)y+16(y^2)]=2[(x^2)-16y][(x^2)-y]
49. [(a+2)^2]+ 4a +2(a^2)+1=[(a+2)^2]+ 2a (a+2)+1=(a+2)(a+2+ 2a )+1=(a+2)( 3a +2)+1
=3(a^2)+ 8a +5=( 3a +5)(a+1)
51. (a)(i) 4(x^2)+12xy+9(y^2)= (2x+3y)^2
(a)(ii) 4(x^2)-12xy+9(y^2)= (2x-3y)^2
(b) [4(x^2)+12xy+9(y^2)][ 4(x^2)-12xy+9(y^2)]-9(x^2)
= [(2x+3y)^2][(2x-3y)^2]-[(3x)^2]= {[(2x+3y)(2x-3y)]^2}-[(3x)^2]
= [(2x+3y)(2x-3y)-3x] [(2x+3y)(2x-3y)+3x] or [4(x^2)-9(y^2)-3x] [4(x^2)-9(y^2)+3x]

上面唔明你打咩.....你係唔係想factorize???
51. (a)因式分解(factorize)下列各多項式
(i) 4x2 + 12xy + 9y2
=(2x+3y)(2x+3y)#
(ii) 4x2 – 12xy + 9y2
=(2x+3y)(2x-3y)