1.有向數的運算(+3)+(-4)+(+7),(+4)-(-15)-(-3)
2.代數An=4n-1
3.多頂式7k 2次方 - 6k 2次方 - 8
4.一元一次方程4(3k-10)+21=17
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更新1:
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2008-01-07 4:29 am
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1.有向數的運算(+3)+(-4)+(+7),(+4)-(-15)-(-3)
2.代數An=4n-1
3.多頂式7k 2次方 - 6k 2次方 - 8
4.一元一次方程4(3k-10)+21=17
寫多D解釋比我,吾該呀咁多位
1.有向數的運算(+3)+(-4)+(+7),(+4)-(-15)-(-3)
2.代數An=4n-1
3.多頂式7k 2次方 - 6k 2次方 - 8
4.一元一次方程4(3k-10)+21=17
寫多D解釋比我,吾該呀咁多位
回答 (3)
2008-01-07 4:44 am
✔ 最佳答案
1.有向數的運算(+3)+(-4)+(+7)=3-4+7=-1+7=-6 (+4)- (-15)-(-3)=4+15+3=22
2.代數An=4n-1
An-4n=-1
n(A-4)=-1
n=-1/A-4
3.多頂式7k 2次方 - 6k 2次方 - 8
=(7k 2次方 - 6k 2次方)-8
=k 2次方-8
4.一元一次方程4(3k-10)+21=17
4(3k-10)=17-21
3k-10=-4/4
3k=-1-10
k=-11/3
參考: me
2008-01-07 6:33 am
檢舉
1.有向數的運算(+3)+(-4)+(+7)=3-4+7=-1+7=-6
(+4)- (-15)-(-3)=4+15+3=22
2.代數An=4n-1
An-4n=-1
n(A-4)=-1
n=-1/A-4
3.多頂式7k 2次方 - 6k 2次方 - 8
=(7k 2次方 - 6k 2次方)-8
=k 2次方-8
4.一元一次方程4(3k-10)+21=17
4(3k-10)=17-21
3k-10=-4/4
3k=-1-10
k=-11/3
1.有向數的運算(+3)+(-4)+(+7)=3-4+7=-1+7=-6
(+4)- (-15)-(-3)=4+15+3=22
2.代數An=4n-1
An-4n=-1
n(A-4)=-1
n=-1/A-4
3.多頂式7k 2次方 - 6k 2次方 - 8
=(7k 2次方 - 6k 2次方)-8
=k 2次方-8
4.一元一次方程4(3k-10)+21=17
4(3k-10)=17-21
3k-10=-4/4
3k=-1-10
k=-11/3
參考: me
2008-01-07 4:59 am
1.有向數的運算(+3)+(-4)+(+7),(+4)-(-15)-(-3)
(+3)+(-4)+(+7) = 3 - 4 + 7 = 6
(+4)-(-15)-(-3) = 4 + 15 +3 = 22
2.
An=4n-1
An - 4n = - 1
n (A - 4) = -1
n = - 1 / A -4
3.多頂式7k 2次方 - 6k 2次方 - 8
=(7k 2次方 - 6k 2次方)-8
=k 2次方-8
4.
4(3k-10)+21=17
12k - 40 +21 = 17
12k - 19= 17
12k - 19 + 19 = 17 + 19
12k =36
12k / 12 = 36 / 12
k = 3
2008-01-06 21:01:34 補充：
MSN : [email protected]
(+3)+(-4)+(+7) = 3 - 4 + 7 = 6
(+4)-(-15)-(-3) = 4 + 15 +3 = 22
2.
An=4n-1
An - 4n = - 1
n (A - 4) = -1
n = - 1 / A -4
3.多頂式7k 2次方 - 6k 2次方 - 8
=(7k 2次方 - 6k 2次方)-8
=k 2次方-8
4.
4(3k-10)+21=17
12k - 40 +21 = 17
12k - 19= 17
12k - 19 + 19 = 17 + 19
12k =36
12k / 12 = 36 / 12
k = 3
2008-01-06 21:01:34 補充：
MSN : [email protected]
參考: 自己
收錄日期: 2021-05-01 15:40:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080106000051KK04133