1.設一動直線與x軸和y軸分別交於點A和B,而三角形OAB的面積恒為4平方單位。P為線段AB的分點,且AP:PB=3:2。試求點P的軌跡方程。
2.點M在曲線y^2=8x+4上移動。過點M的一直線L垂直於直線X+3=0。垂足為Q。若M為PQ的中點,求點P的軌跡方程。
要過程~~THX
F5軌跡方程(10分)
2008-01-06 11:39 pm
回答 (2)
2008-01-07 12:08 am
✔ 最佳答案
1: letp[x,y]is on the locusB[a,o] A[o,b]
ab/2=4
ab=8.....[1]
X=3a/5 Y=2b/5
5X/3=a....[2] 5y/2=b....[3]
5X/3.5Y/2=8
25XY/6=8
25XY=48
2:我唔明ＬＥＥ句〔過點M的一直線L垂直於直線X+3=0。垂足為Q。〕
2008-01-07 1:19 am
i give you the answer of 2. because someone had already answered.
plz see the hyperlink.
http://www.hkedcity.net/sch_files/a/kst/kst-06185/public_html/y^2.jpg
hope that i have not conceptual mistakes.
enjoy.
2008-01-06 17:22:28 補充：
i sure that my method is not the most clever method, plz give the best answer to someone who can slove the problem in a more simpler way.========================for question no.1, i also do it like 樓上.
plz see the hyperlink.
http://www.hkedcity.net/sch_files/a/kst/kst-06185/public_html/y^2.jpg
hope that i have not conceptual mistakes.
enjoy.
2008-01-06 17:22:28 補充：
i sure that my method is not the most clever method, plz give the best answer to someone who can slove the problem in a more simpler way.========================for question no.1, i also do it like 樓上.
收錄日期: 2021-05-03 04:34:55
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080106000051KK02360