"A man sold 3/5 of his land. He had 15 3/4 hectares left. How much land had he at first?"?

If you sell 3/5 of your land, then you have 2/5 left. So, divide 15 3/4 by 2/5. You get 39 3/8 hectacres

2/5<---->15¾ hectares
5/5<---->(5/2) x 15¾ = (5/2) x (63/4) hectares
315 / 8 hectares
39 ⅜ hectares

Method 1
15 3/4 ÷ (1 - 3/5)
= 15 3/4 ÷ 2/5
= 63/4 x 5/2
= 315/8
= 39 3/8 hectares

Method 2
y x (1 - 3/5) = 15 3/4
y x 2/5 = 15 3/4
y = 15 3/4 ÷ 2/5
y = 63/4 x 5/2
y = 315/8
y = 39 3/8

Let X = how much he had at first

Since he sold 3X/5, he has 2X/5 left (1-3X/5), so
2X/5 = 15 3/4

Just solve for X =)

he had 5/3 of 15 3/4 hectares = 25 5/4 hect = 26 1/4 hectares

15 3/4 hectares is 2/5 of the original. So, you make 1/5 by dividing 15 3/4 by 2 (=7 7/8) then you multiply that by 5 to make the answer.

15.75/2 = 7.875
7.875 x 5 =

Answer = 39 3/8 hectares

16 7/20 is the answer