數學﹗﹗數學(指數)!!

2008-01-06 3:26 am
問題1)2.4^n=2^3n

2)(32^n)^n=4.2^3

3)(6^n)=2^2X3^2

P.S問題3的答案係唔係2????

回答 (2)

2008-01-06 5:16 am
✔ 最佳答案
(2.4)^n=2^(3n)
n log 2.4= 3n log2
( 3 log 2 - log 2.4)n=0
n=0

不過我唸你打錯...應該係
2x4^n=2^(3n)
2^(1+2n)=2^(3n)
1+2n=3n
n=1

(32^n)^n=4.2^3
32^(n^2)=4.2^3
(n^2) log 32= 3 log 4.2
n=1.114555336
or n= -1.114555336

不過我唸你都係打錯...應該係
(32^n)^n=4x2^3
32^(n^2)=32
n^2=1
n=1
or n= -1

(6^n)=2^2X3^2
6^n=4x9
6^n=36
6^n=6^2
n=2
係2丫
2008-01-06 4:05 am
係要搵個n出黎定點??講清楚dd


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