Math Question?

2008-01-04 4:19 pm
Can you figure this out...thx!

Starting form his house, Jesse drives north 6 miles and turns east and drives 2 miles.He turns north again and drives 4 miles and then turns east and drived 7 miles. How far is he from his house? Anything helps....thanks!

回答 (7)

2008-01-04 4:23 pm
✔ 最佳答案
Add up your total north distance and the total east distance. You should get 10 miles north and 9 miles east. Use pythagorean's theorm to find the distance.

10^2+9^2=c^2

100+81=c^2

c= sqrt(181) = approx 13.45 mi.
2008-01-04 4:25 pm
draw it on a piece of paper, label all the lines with their lengths (miles)

then draw a line connecting the start and end point.

then draw a right triangle with the start and end line being the diagonal hyponteneuse. the two sides of the triangle are defined by the lengths of the distances, and pythagoras theorem dictates that A^2 + B^2 == C^2. Solve for C.
2008-01-04 4:25 pm
Hence, Jesse has driven 10 miles north and 9 miles east from his house. You can see this quite easily if you draw it out.

Then use the Pythagoras theory, for right angle triangles,

Distance from house = sq rt (10^2 + 9^2)

Evaluate the rest using a calculator.
2008-01-08 10:13 am
His location is (9, 10)

Distance = sqrt(9^2 + 10^2) = sqrt(181) = 13.45
2008-01-04 4:28 pm
If you draw a diagram, you'll see 2 right triangles for which you'll have to use the Pythogorean theorem to find the hypotenuses.
Add the hypotenuses and you get the distance.
The first triangle sides, 6,2
hyp=sqrt(6^2+2^2)
The second = sqrt(7^2+4^2)
2008-01-04 4:29 pm
It sounds like whoever gave you this math problem was trying to trick you. I'm almost positive that the answer is found by finding the total number of miles he drove, so the correct answer would be:

"Jesse is 19 miles from his house"
2008-01-04 4:25 pm
19 miles


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