maths!!!!!!

2008-01-03 6:24 am
若5sin²θ+3sinθcosθ=1,求tanθ。

回答 (1)

2008-01-03 6:51 am
✔ 最佳答案
5sin²θ+3sinθcosθ=1
Dividing by cos²θ,
5tan²θ + 3tanθ - sec²θ = 0
5tan²θ + 3tanθ -1 - tan²θ = 0
4tan²θ + 3tanθ - 1 = 0
( 4tanθ - 1 )( tanθ + 1 ) = 0
tanθ = 1 / 4 or -1
參考: My Maths Knowledge


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