Can anyone help me solve this math problem (3x-2y)2=?

Reading this as :-
(3x - 2y) ² = 9 x ² - 12 x y + 4 y ²

6x-4y

(3x-2y)2
= 3x * 2 - 2y * 2
= 6x - 4y

Firstly, the equation cannot be solved because we do not know what the variables are, and because there is no value on the right side of your equal sign. Even if there were a value given on the right side, we still wouldn't know what x and y are.

Perhaps this might be interesting for you:
It doesn't matter which way you multiply things.
4 x 5 = 20
5 x 4 = 20
And so, variables and numbers in algebra follow the same rules (of course).

(3x-2y)2 means the same as
2(3x-2y)

We multiply each term within the brackets by the 2 (and add each product):
2 times 3x + (2 times -2y)
6x + (-4y)
6x - 4y

You can always check your own work by subbing in simple numbers for x and y and see if things still jive!

For instance, we could let
x=1
y=2
Just to check out stuff (we really don't know what x and y are)

Plugging in these test values for x and y into your equation looks like so:

((3)(1) -(2)(2))times 2 = -2
Now sub these same values for x and y into our final expression (expanded expression):

6x -4y
6(1) -4(2)
equals negative two, so yes the expansion of your expression was done correctly!

It is possible that you meant to say:
(3x-2y)^2, in which case look at 'Daniel G' above for instructions (and perhaps consider Daniel for the best answer).

Place the two on the left side. Now we have 2(3x - 2y). Now solve, you should get 6x - 4y.

1 1/2 X-Y

(3x-2y)^2=9x^2-12xy+4y^2