In a box of oranges, the number of rotten oranges is 19分之1of the total number of oranges. If 3more rotten oranges are put into the box ,the total number of rotten oranges is 10分之1of the total number of oranges.
(a) find the original number of rotten oranges in the box.
(b) find the final number of oranges in the box.
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2008-01-02 6:58 am
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2008-01-02 7:18 am
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Q: In a box of oranges, the number of rotten oranges is 1/19 of the totalnumber of oranges. If 3 more rotten oranges are put into the box, the
total number of rotten oranges is 1 / 10 of the total number of oranges.
( a ) Find the original number of rotten oranges in the box?
( b ) Find the final number of oranges in the box?
Sol:
( a ) Suppose x is the original number of rotten oranges,
then the original total number of oranges is 19x
x ＋ 3 ＝ 1/10 * ( 19x ＋ 3 )
10x ＋ 30 ＝ 19x ＋ 3
27 ＝ 9x
x ＝ 3
( b )
final number = original number + 3
19 × 3 ＋ 3 ＝ 60
Ans: ( a ) 3 rotten oranges ( b ) 60 oranges
參考: 數學小頭腦
2008-01-02 7:27 am
Let x be the original number of oranges in the box,
x/19 + 3 = x+3/10
10x + 570 = 19x + 57
513 = 9x
x = 57
a) The original number of rotten oranges in the box = 57/19 = 3
b) The final number of oranges in the box = 57 + 3 = 60
x/19 + 3 = x+3/10
10x + 570 = 19x + 57
513 = 9x
x = 57
a) The original number of rotten oranges in the box = 57/19 = 3
b) The final number of oranges in the box = 57 + 3 = 60
參考: me
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