.3(2c-d)x+c-d≡18x+1
Find c and d.
Maths Identities HELP THX
2008-01-02 5:00 am
回答 (2)
2008-01-02 10:38 pm
✔ 最佳答案
3(2c-d)X+c-d = 18X + 1(6c-3d)X + c-d = 18X + 1
=>6c-3d = 18 ------------- (1)
and c-d = 1
=>c = d+1 ------------(2)
sub (2) into (1) we get
6(d+1) - 3d = 18
=> 6d + 6 - 3d = 18
=> 3d = 12
=> d = 4 ---------- (3)
sub (3) into (2) we get
c = 4 + 1 = 5
2008-01-10 12:22 am
3(2c-d)x+c-d=18x+1
18x+1
18÷3=6
6=2c-d
假設c=3 d=3
2×3+3=9 3×9=27 不成立
9分成5及4
3(2×5-4)X+5-4=18X+1
=3x6X+1=18X+1
=18X+1=18X+1 成立
18x+1
18÷3=6
6=2c-d
假設c=3 d=3
2×3+3=9 3×9=27 不成立
9分成5及4
3(2×5-4)X+5-4=18X+1
=3x6X+1=18X+1
=18X+1=18X+1 成立
收錄日期: 2021-04-14 18:14:08
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https://hk.answers.yahoo.com/question/index?qid=20080101000051KK03923