Find the partial fraction of:
(3s^2 + 4) / ((s+1)(s^2 + 1))
Partial fraction
2008-01-02 1:27 am
回答 (1)
2008-01-02 1:38 am
✔ 最佳答案
let (3s^2 + 4) / ((s+1)(s^2 + 1)) = A / (s+1) + (Bs +C) / (s^2 +1)Then by comparing coefficient, we have
A+B = 3
B + C = 0
A+C = 4
Thus,
A = 7/2
B = -1/2
C = 1/2
Therefore,
(3s^2 + 4) / ((s+1)(s^2 + 1)) = [7 / (s+1) + (-s +1) / (s^2 +1)] / 2
收錄日期: 2021-04-11 17:30:28
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