緊急!!中4數學題目!!

2008-01-02 12:53 am
1.)當-x^3 +97x 加上x^3+2x^2-x+1 時,所得的多項式的次數是多少?

2.)求2x+1乘以5-x^2所得的積,並把答案依x的降幂排列

3.)求(2x^3+x^2-3x+1)/(x^2-x+1)的商式和餘式

4.)求當多項式3x^2005+2005x-3除以x-1時所得的餘數

5.)若8x^3-2x^2+kx+1可被2x-1整除,求k的值

6.)已知x+2是2x^3+ax^2+dx+1 的因式,求-4a+2b的值

7.)利用因式定理,因式分解x^3-6x^2+11x-6

回答 (2)

2008-01-02 1:03 am
✔ 最佳答案
1.)當-x^3 +97x 加上x^3+2x^2-x+1 時,所得的多項式的次數是多少?
-x^3 + 97x + x^3 + 2x^2 - x + 1
= 2x^2 + 97x - x + 1
多項式的次數 = 2
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2.)求2x+1乘以5-x^2所得的積,並把答案依x的降幂排列
(2x + 1)(5 - x^2)
= (2x) (5 - x^2) + (1) (5 - x^2)
= 10x - 2x^3 + 5 - x^2
= -2x^3 - x^2 + 10x + 5
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3.)求(2x^3+x^2-3x+1)/(x^2-x+1)的商式和餘式
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4.)求當多項式3x^2005+2005x-3除以x-1時所得的餘數
let f(x) = 3x^2005 + 2005x - 3
餘數 = f(1) = 3(1^2005) + 2005(1) - 3 = 2005
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5.)若8x^3-2x^2+kx+1可被2x-1整除,求k的值
let f(x) = 8x^3 - 2x^2 + kx + 1
f(1/2) = 8(1/2)^3 - 2(1/2)^2 + k(1/2) + 1 = 0
1 - 1/2 + k/2 + 1 = 0
k = -3
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6.)已知x+2是2x^3+ax^2+dx+1 的因式,求-4a+2b的值
let f(x) = 2x^3 + ax^2 + dx + 1
f(-2) = 2(-2)^3 + a(-2)^2 + d(-2) + 1 = 0
-16 + 4a - 2d + 1 = 0
4a - 2d = 15
-4a + 2b = -15
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7.)利用因式定理,因式分解x^3-6x^2+11x-6
自己做埋佢, 太多題
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2008-01-02 1:05 am
7.)x^3-6x^2+11x-6

f(1)=(1)^3-6(1)^2+11(1)-6
=1-6+11-6
=0
希望幫到你啦


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