How to do these : [ I want the step ]
1.Factorize 9p+12pq+18pqr [answer is 3p(3+4q+6qr) ]
2.Make [ u ] the subject of the formula y=t(11+9u) [answer is u = v/9t - 11/9 ]
3.Given that q=(3-p) / (p+1), find the value of p when q = -(1/2) [answer is 7 ]
4.Make t the subject of the formula (rt-1) / (r) =1- (2t) / (s) [ answer is t =rs+s/rs+2r ]
5.Make k the subject of the formula 5/(h-10)= 1/(5-k) [ answer is k=(35-h) /5 ]
P.S : Step !!! I want the Step !!! thank you !
Quickly !!! Maths !! Plz !! THX !!! ( 10 point !! )
2007-12-30 10:06 pm
回答 (2)
2007-12-30 10:27 pm
✔ 最佳答案
1.抽3p出黎就=3p(3+4q+6qr)2.y=(11+9u)t *兩邊除t
11+9u=y/t *兩邊-11
u=(y/t-11)/9 *兩邊除9
=y/9t - 11/9 *答案
3.將q=-1/2代入前面的公式
3-p/p+1=-1/2 *兩邊乘2(p+1)以消去分母
3-p = -1/2(p+1)
2(3-p) = -p-1
6-2p = -p-1
p = 7
4. 先將兩邊乘rs以消去分母,再移項就ok
(rt-1)s = rs - (2r)t
(rs)t -s = rs - (2r)t
(rs+2r)t=rs+s
t=rs+s/rs+2r
5.5(5-k)= h-10
25-5k = h-10
-5k = h -35
k = 35-h/5
2007-12-30 10:32 pm
1.9p+12pq+18pqr
=3(3p+4pq+6pqr)
=3p(3+4q+6qr)
2.y=t(11+9u) [ u ]
y=11t+9ut
y-11t=9ut
u=y/9t-11/9
3.q=(3-p) / (p+1)
-(1/2)=(3-p)/(p+1)
-[(p+1)/2]=3-p
6-2p= -p-1
p=7
4.(rt-1) / (r) =1- (2t) / (s) [ t ]
rts-s=r-2tr
t(rs+2r)=r+s
t=(r+s)/(rs+2r)
5. 5/(h-10)= 1/(5-k) [k]
25-5k=h-10
35-h=5k
k=(35-h)/5
=3(3p+4pq+6pqr)
=3p(3+4q+6qr)
2.y=t(11+9u) [ u ]
y=11t+9ut
y-11t=9ut
u=y/9t-11/9
3.q=(3-p) / (p+1)
-(1/2)=(3-p)/(p+1)
-[(p+1)/2]=3-p
6-2p= -p-1
p=7
4.(rt-1) / (r) =1- (2t) / (s) [ t ]
rts-s=r-2tr
t(rs+2r)=r+s
t=(r+s)/(rs+2r)
5. 5/(h-10)= 1/(5-k) [k]
25-5k=h-10
35-h=5k
k=(35-h)/5
參考: me
收錄日期: 2021-04-23 21:28:44
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071230000051KK01529