Who Knows how to reduce -39/120.?

-39/120 is a fraction obviously. To reduce, you have to find a common multiple they both share that you can divide them equally by. Heres how it works

1.) Try a few numbers, 39 is not divisible by 2 so try 3. It is.
2.) 39/3 = 13
3.) 120/3 = 40
4.) The last step is to rewrite as a fraction - 13/40

There ya go! Hope that helped!

= - 39/120
= - 13/40

- 39 / 120 = - 13 / 40

steps:

1. what goes into 39 and 120 evenly?

2. is it reduced to its smallest?

3. a negative divided by a positive is a ____

i didnt solve it for you, you should learn how.

numerator and denominator reduce by a factor of 3:

-39/3 = - 13
120/3= 40

ans. -13/40

that's it! :)

-39/120
= -39÷3/120÷3
= -13/40

lowest common denominator is 3... you can tell because when you add all digits together, they equal a number divisible by 3 (i.e.: 39... 3+9=12... 1+2=3) (120...1+2+0=3). so you divide 39 by 3 = 13, then divide 120 by 3 = 40. 13 is a prime number so it is reduced as far as it can go... -13/40.

reduce by a factor of three:

-39/120 = (-13 X 3) / (40 X 3) = -13/40

both -39 and 120 are divisible by 3. -39/3 = -13 and 120/3 = 40. therefore, -39/120 = -13/40

-13/40

-39/120 find the lcm and divide by it and this case it is 3

-39/120/ 3/3=-13/40