F.4 Maths
回答 (2)
2007-12-30 2:50 am
∵no real roots
∴△＜0
△ = [2(2-p)]2-4(1-p)(1-p)＜0
(4-2p)2-(2-2p)2＜0
(4-2p+2-2p)(4-2p-2+2p)＜0
(6-4p)(2)＜0
6-4p＜0
6＜4p
1.5＜p
P＞1.5
∴△＜0
△ = [2(2-p)]2-4(1-p)(1-p)＜0
(4-2p)2-(2-2p)2＜0
(4-2p+2-2p)(4-2p-2+2p)＜0
(6-4p)(2)＜0
6-4p＜0
6＜4p
1.5＜p
P＞1.5
收錄日期: 2021-04-13 14:49:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071229000051KK02994