化簡f.2

1)p-q+0.5(p+q)/p
2)-1b/24a
3)1-(x/y-1)
4)2又a-b/a+b
5)唔識
6唔識
本人小六,純粹玩野,唔好以為我識-.-

1. 你意思係 p-q/p 定 (p-q)/p?
前者:: p-q/p + p+q/2p
=2p-(2q+q)/2p __ [通分母]
=2p-3q/2p
後者:: (p-q)/p + (p+q)/2p
= [2 (p-q) /2p] + [(p+q)/2p] __ [通分母]
= (2p -2q +p +q) /2p
= (3p -q)/ 2p

2. b/8a +b/12a - 7b/24a
= (3b +2b -7b )/24a __ [通分母]
= -2b/ 24a
=-b/12a

3. 1 - x-y/y (我想應該是 1-(x-y)/y 吧)
= y/y - (x-y)/y
= (y-x-y) /y
= - x/y

4.a-b/a+b +2 (我當它是 (a-b)/(a+b) +2
= (a-b)/(a+b) + (2a+2b)/ (a+b)
= (a-b+2a+2b)/( a+b)
= (3a +b )/(a+b)

5. pq+q+p+1/3(p+1)
這個是 (pq+q+p+1)/3(p+1) 嘛?
=[q(p+1)+(p+1)]/3(p+1)
=[(p+1)(q+1)]/3(p+1)
=(q+1)/3

6. (25a^2-b^2)/(5a-b)
=[(5a-b)(5a+b)]/(5a-b) __[Identity >Difference of two squares]
=5a+b

1. p-q/p + p+q/2p
= 2 (p-q) /2p + p+q/2p
= 2p -2q +p +q /2p
= 3p -q/ 2p

2. b/8a +b/12a - 7b/24a
= 3b +2b -7b /24a
= -2b/ 24a

3. 1 - x-y/y
= y/y - x-y/y
= y-x-y /y
= - x/y

4. a-b/a+b +2
= a-b/a+b + 2a+2b/ a+b
= a-b+2a+2b/ a+b
= 3a +b /a+b

5. pq+q+p+1/3(p+1)
6. 25a^2-b^2/5a-b
I don't konw, sorry~