Sally finishes a race in 4 min 37 s, and the error of this measurement is at most 0.5 s. What is the percentage error of this measurement? (Give the answer cor. to the nearest 0.1%)
Thanks!!
Maths Question
2007-12-28 11:57 am
回答 (3)
2007-12-28 4:31 pm
✔ 最佳答案
Sally's time:=4*60+37
=277sec.
The percentage error:
=0.5/277*100%
=0.180505415%
=0.2%(cor. to the nearest 0.1%)
★希望能夠幫助你吧★
2007-12-28 12:31 pm
4 min 37 s = (4 x 60) + 37 = 277 s
(277/0.5)/100 = 5.54
So, the percentage error of this measurement is 5.5%
2007-12-28 04:33:30 補充：
Sorry, I think the above person is right. (0.5/277) x 100% = 0.2%
(277/0.5)/100 = 5.54
So, the percentage error of this measurement is 5.5%
2007-12-28 04:33:30 補充：
Sorry, I think the above person is right. (0.5/277) x 100% = 0.2%
參考: me
2007-12-28 12:27 pm
4 min 37 s = 4*60+37s=277s, therefore 0.5s is 0.5/277*100%=0.2%
收錄日期: 2021-04-13 14:48:56
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