✔ 最佳答案
Q: 甲及乙兩個容器中盛有濃度不同的鹽水, 若從甲及乙容器各取出重量相等的
鹽水, 將它們混合後得到濃度是 10% 的鹽水 ( 即鹽的重量是鹽水的重量的
10% ); 若從甲容器中取出 2 份鹽水, 從乙容器中取出 3 份鹽水, 每份鹽水的
重量相同, 混合後就成為含鹽量是 7% 的鹽水. 求:
( a ) 甲容器內鹽水的濃度?
( b ) 乙容器內鹽水的濃度?
Sol:
Let
x be the ratio of salt water of container 甲, and
y be the ratio of salt water of container 乙
then
( x + y ) / 2 = 10
x + y = 20 ....... ( 1 )
( 2x + 3y ) / 5 = 7
2x + 3y = 35 ....... ( 2 )
( 2 ) - ( 1 ) * 2
y = - 5
x + y = 20
x = 25
Your question is wrong.
Ans: No solution
2007-12-28 17:24:34 補充:
I know.But I have check the answer for many times, still get "no solution". sorry.Or can you check the question again, please?