Find an equation in x and y by eliminating t from the parametric equation:
x=1-t2/1+t2
y=2t/1+t2
parametric equation
2007-12-28 5:08 am
回答 (1)
2007-12-28 5:58 am
✔ 最佳答案
From x=(1-t^2)/(1+t^2)(1+t^2)x=(1-t^2)
(1+x)t^2=1-x
So t^2=(1-x)/(1+x) and t=√(1-x)/(1+x),
substitute into y=2t/(1+t^2),
y
=2t/(1+t^2)
=2[√(1-x)/(1+x)]/[2/(1+x)]
=√(1-x)(1+x)
We get x^2+y^2=1 and this is the equation in x and y by eliminating t from the parametric equation
收錄日期: 2021-04-26 13:04:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071227000051KK04540